- #1

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Its diifcult to express my question....so, i am posting this

ceil(4.5) =?

ceil(4.1)=?

ceil(4.6)=?

ceil(4.5) =?

ceil(4.1)=?

ceil(4.6)=?

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- Thread starter momentum
- Start date

- #1

- 111

- 0

Its diifcult to express my question....so, i am posting this

ceil(4.5) =?

ceil(4.1)=?

ceil(4.6)=?

ceil(4.5) =?

ceil(4.1)=?

ceil(4.6)=?

- #2

AKG

Science Advisor

Homework Helper

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- #3

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ceil(4.5)=4 // is it ok ?

ceil(4.1)=4 //is it ok ?

ceil(4.6)=5 //is it ok ?

ceil(4.1)=4 //is it ok ?

ceil(4.6)=5 //is it ok ?

- #4

Integral

Staff Emeritus

Science Advisor

Gold Member

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Nope, read the defintion given above, then try again.momentum said:ceil(4.5)=4 // is it ok ?

ceil(4.1)=4 //is it ok ?

ceil(4.6)=5 //is it ok ?

- #5

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but i see ..it does not care for .5 which we use for round-off.

- #6

Curious3141

Homework Helper

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Yes, all 5.

- #7

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thank you for the clarifcation

- #8

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Recall that

[tex]\begin{gathered}

\forall x \in \left( {a,a + 1} \right)\;{\text{where }}a \in \mathbb{Z}, \hfill \\

{\text{floor}}\left( x \right) = \left\lfloor x \right\rfloor = a \hfill \\

{\text{ceil}}\left( x \right) = \left\lceil x \right\rceil = a + 1 \hfill \\

\end{gathered} [/tex]

[tex]\forall x \in \mathbb{Z},\;\left\lfloor x \right\rfloor = \left\lceil x \right\rceil = x [/tex]

[tex]\begin{gathered}

\forall x \in \left( {a,a + 1} \right)\;{\text{where }}a \in \mathbb{Z}, \hfill \\

{\text{floor}}\left( x \right) = \left\lfloor x \right\rfloor = a \hfill \\

{\text{ceil}}\left( x \right) = \left\lceil x \right\rceil = a + 1 \hfill \\

\end{gathered} [/tex]

[tex]\forall x \in \mathbb{Z},\;\left\lfloor x \right\rfloor = \left\lceil x \right\rceil = x [/tex]

Last edited:

- #9

jim mcnamara

Mentor

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floor -> "goes down" as it needs to, in order to reach an integer

What happens with negative numbers:

[tex] floor( -1.1 ) = -2 \; ceil( -1.1 ) = -1 [/tex]

[tex] floor( -0.1 ) = -1 \; ceil( -0.1 ) = 0 [/tex]

[tex] floor( 0.9 ) = 0 \; ceil( 0.9 ) = 1[/tex]

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